Jenis Jenis Jaringan Komputer

OSI Layer 3 – Network / Jaringan

Lapisan jaringan model OSI bertanggung jawab untuk pengiriman paket dari ujung ke ujung.

Ini dilakukan dengan menggunakan skema pengalamatan lain yang secara logis dapat mengidentifikasi setiap node yang terhubung ke Internet. Skema pengalamatan ini dikenal sebagai alamat Internet Protokol atau Alamat IP.

Itu dianggap logis karena alamat IP bukan merupakan identifikasi permanen komputer. Berbeda dengan alamat MAC yang dianggap sebagai alamat fisik, alamat IP tidak dibakar ke perangkat keras komputer apa pun oleh pabrikan.

Router adalah Perangkat Jaringan yang beroperasi pada Layer 3 dari model OSI. Tanggung jawab utama Router adalah memfasilitasi komunikasi antar Jaringan. Dengan demikian, Router menciptakan batas antara dua jaringan. Untuk berkomunikasi dengan perangkat apa pun yang tidak secara langsung di jaringan Anda, router harus digunakan.

 

 

Hierarchical Classification of Average Linkage Euclidean Distance

The classification hierarchy will use Euclidean distance.
The data we will use is as follows:

The initial stage is to calculate data X and data Y.
At this stage, the calculation method is different from the others.
The calculation stages are as follows:

• D1,D1 means sqrt((X1-X1) ^ 2 + (Y1-Y1) ^ 2) (using euclidean distance)
• D1,D2 means sqrt((X1-X2) ^ 2 + (Y1-Y2) ^ 2) (using euclidean distance)
• D1,D3 means sqrt((X1-X3) ^ 2 + (Y1-Y3) ^ 2) (using euclidean distance)
• D1,D4 means sqrt((X1-X4) ^ 2 + (Y1-Y4) ^ 2) (using euclidean distance)
• D1,D5 means sqrt((X1-X5) ^ 2 + (Y1-Y5) ^ 2) (using euclidean distance)
• D2,D2 means sqrt((X2-X2) ^ 2 + (Y2-Y2) ^ 2) (using euclidean distance)
• D2,D3 means sqrt((X2-X3) ^ 2 + (Y2-Y3) ^ 2) (using euclidean distance)
• D2,D4 means sqrt((X2-X4) ^ 2 + (Y2-Y4) ^ 2) (using euclidean distance)
• D2,D5 means sqrt((X2-X5) ^ 2 + (Y2-Y5) ^ 2) (using euclidean distance)
• D3,D3 means sqrt((X3-X3) ^ 2 + (Y3-Y3) ^ 2) (using euclidean distance)
• D3,D4 means sqrt((X4-X4) ^ 2 + (Y4-Y4) ^ 2) (using euclidean distance)
• D3,D5 means sqrt((X5-X5) ^ 2 + (Y5-Y5) ^ 2) (using euclidean distance)
• D4,D4 means sqrt((X4-X4) ^ 2 + (Y4-Y4) ^ 2) (using euclidean distance)
• D4,D5 means sqrt((X4-X5) ^ 2 + (Y4-Y5) ^ 2) (using euclidean distance)
• D5,D5 means sqrt((X5-X5) ^ 2 + (Y5-Y5) ^ 2) (using euclidean distance)

The results are as follows:

Next is to create a matrix diagram :

From the matrix above, we will choose the smallest result except 0 and it turns out that the smallest value is 1.414213562 which belongs to data 3 to 5 and 5 to 3.
We will combine the data to form the following:

• D(35)1
• D(35)2
• D(35)4

Next, the average value will be calculated from the data, as follows:

• D(35)1 = average(5.830951895 , 6.32455532) = 6.077753608
• D(35)2 = average(2.828427125 , 3.16227766) = 2.995352392
• D(35)4 = average(5.385164807 , 4.123105626) = 4.754135216

The results obtained are as follows:

After obtaining the data, the smallest value is selected to form a matrix as follows:

After that, the smallest data from the data above is selected again, so that what is obtained is as follows:

• D(352)1
• D(352)4

The results obtained are as follows:

After obtaining the data, the smallest value is selected to form a matrix as follows:

After that, the smallest data from the data above is selected again, so that what is obtained is as follows:

• D(3524)1

The results obtained are as follows:

After obtaining the data, the smallest value is selected to form a matrix as follows:

From the results above, we can create a diagram, so that the diagram is formed as follows: